Force = Mass x Acceleration, or f=ma. a = (v-u)/t, therefore, f=m(v-u)/t, f=rate of change of momentum.
If f is a constant i.e. you can't give your muscles additional strength in a short period of time to increase the force they supply, then u=0; At the top of the backlift there is no velocity. As m increases, v must therefore decrease and vice versa for a given f. Bear in mind that g (gravity) will also help accelerate.
To this end, the only way to increase v for a given m is by increasing f, or in other words, increasing your strength.
Surely if you are striking the ball with an object that has more mass then more power is transferred to the ball? ie if I drive into the back of a range rover on my 'blade at 30 mph then I will probably dent it a bit (and die) but if I drive into the back of the range rover in my car at 30 mph then I will probably push it forward a few feet?
I'm confused!
If bat weight really doesn't make any difference at all to shot power then I think I might have to buy something light.....which is as good a reason as any to buy another bat!
Yes, this is true, but what you are looking for is force. In both these cases, the acceleration, a is huge, and the bike has a lower mass so therefore exerts much less force on the car in front.
Equally, the force required for the bike to accelerate up to 30mph is much lower because the bike has a lower mass, so your 'blade does 0-60 with an engine producing 120 hp in 3 secs, whereas your car with an engine producing 150 hp takes 8 seconds because it has only 1.25 times the force to apply and weighs more than twice as much...