Swing speed or bat volume
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Author Topic: Swing speed or bat volume  (Read 10408 times)

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Buzz

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Re: Swing speed or bat volume
« Reply #45 on: March 15, 2010, 03:04:39 PM »

Momentum = Mass x Velocity

There is a point where (High Mass x Low Velocity) is equivalent to (Low Mass x High Velocity).

I think its all about controlling the blade of the bat. which one does for you is an another matter

that's what I was trying to say!!
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norbs

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Re: Swing speed or bat volume
« Reply #46 on: March 15, 2010, 11:46:20 PM »

Andy - anything to add to this, would be good to hear your opinion and the science behind it.

It is a complex question this one!!!

Colesy

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Re: Swing speed or bat volume
« Reply #47 on: March 15, 2010, 11:54:40 PM »

Personal preference at the end of the day, I prefer bat volume but I can see why most would take speed.
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norbs

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Re: Swing speed or bat volume
« Reply #48 on: March 16, 2010, 10:19:30 AM »

Momentum = Mass x Velocity

There is a point where (High Mass x Low Velocity) is equivalent to (Low Mass x High Velocity).

I think its all about controlling the blade of the bat. which one does for you is an another matter

Batted ball speed = q x Velocity of ball + (1 + q)Velocity of bat

Buzz

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Re: Swing speed or bat volume
« Reply #49 on: March 16, 2010, 10:24:44 AM »

what does q = ?

quality of wood from the SAF Richter scale?
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norbs

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Re: Swing speed or bat volume
« Reply #50 on: March 16, 2010, 10:27:57 AM »

what does q = ?

quality of wood from the SAF Richter scale?

nope, q is the Bouncabilty of a bat or the Apparent Coefficient of Restitution [ACoR]

SillyShilly

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Re: Swing speed or bat volume
« Reply #51 on: March 16, 2010, 10:31:42 AM »

q = kettle drum?
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norbs

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Re: Swing speed or bat volume
« Reply #52 on: March 16, 2010, 10:45:20 AM »

nope, q is the Bouncabilty of a bat or the Apparent Coefficient of Restitution [ACoR]

So....

Which Cricket bat is better, stick with me here….

 [A Big Note: Made up numbers for q and velocity but proper calculations with those numbers]

A normal cricket bat our datum point….

q = 0.45
Vel of Bat = 50
Vel of ball = 60
Ball exit speed is 99.5



Now add 10% on the cricket bat mass resulting in a slightly lower bat speed lets say 10% slower and lets keep it 10% and increase in q [bouncabilty] which is Apparent CoR or [ACOR]

So
q = 0.5
Vel of bat = 45
Vel of ball = 60
Ball exit speed is 97.5

Ok let assume you have a bat and the swing weight is the same as first bat but has more mass therefore a higher q [ACOR]

q = 0.5
Vel of Bat = 50
Vel of ball = 60
Ball exit speed is 105

-----

There is another caveat here though

Buzz

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Re: Swing speed or bat volume
« Reply #53 on: March 16, 2010, 10:48:45 AM »

surely "quantum of ping" or "quop"
loving the science though Norbs
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SillyShilly

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Re: Swing speed or bat volume
« Reply #54 on: March 16, 2010, 11:03:15 AM »

Hurry up with the caveat, the suspense is killing me!
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norbs

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Re: Swing speed or bat volume
« Reply #55 on: March 16, 2010, 11:19:09 AM »

Hurry up with the caveat, the suspense is killing me!

So what do those theoretical values tell us…

Swing speed offset against bat weight if you plotted it on a graph is on curve, slowly raises and plato’s and then slowly drops off.

Therefore there is a range of bat weights that with good pickup will allow you to have the same reaction time and swing speed due to the weight distribution in the bat

Mass behind the sweet spot [hopefully in the main hitting area] will be ideal especially if the swing weight of the bat means you are hitting the ball at close to maximum speeds in the position and batting shapes you normally hit a ball at…

Does this mean there is an optimum weight for everyone, depending on their strength?

Yes this optimum weight would be where they could swing the bat fastest without to much compromise on size of the bat.


Ok Willow is organic a live piece of timber and you will never really know how a bat will go until it is used. Yes it is complex  due to the numerous varibles associated to the timber and person using it and level at which it is all used. [As a little note: it is even more complex then this, it has been dumbed down quite a lot]

Finally…..
You don’t always slog the ball and I will agree with you pratical, theoretical and variation on ball, bat and bowling speeds doesn’t make it conclusive but you can get a good baseline and it makes for good read!!!!

RossViper

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Re: Swing speed or bat volume
« Reply #56 on: August 09, 2011, 09:24:37 AM »

So....

Which Cricket bat is better, stick with me here….

 [A Big Note: Made up numbers for q and velocity but proper calculations with those numbers]

A normal cricket bat our datum point….

q = 0.45
Vel of Bat = 50
Vel of ball = 60
Ball exit speed is 99.5



Now add 10% on the cricket bat mass resulting in a slightly lower bat speed lets say 10% slower and lets keep it 10% and increase in q [bouncabilty] which is Apparent CoR or [ACOR]

So
q = 0.5
Vel of bat = 45
Vel of ball = 60
Ball exit speed is 97.5

Ok let assume you have a bat and the swing weight is the same as first bat but has more mass therefore a higher q [ACOR]

q = 0.5
Vel of Bat = 50
Vel of ball = 60
Ball exit speed is 105

-----

There is another caveat here though

yeah, thats not right though norbs is it, at the same speed a more massive bat will produce a higher exit velocity, this question is about the resultant momentum vector. p=mv...  and above has no Mass in the calculation.
« Last Edit: August 09, 2011, 10:41:43 AM by RossViper »
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justnotcricket86

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Re: Swing speed or bat volume
« Reply #57 on: August 09, 2011, 10:38:42 AM »

I just try and smash the red thing
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norbs

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Re: Swing speed or bat volume
« Reply #58 on: August 09, 2011, 10:48:04 AM »

yeah, thats not right though norbs is it, at the same speed a more massive bat will produce a higher exit velocity, this question is about the resultant momentum vector. p=mv...  and above has no Mass in the calculation.

CoR relates to momentum?

tim2000s

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Re: Swing speed or bat volume
« Reply #59 on: August 09, 2011, 11:26:16 AM »

More or less. CoR provides the variation on the velocity caused by an inelastic impact, so effectively adds into the conservation of momentum equation as follows:

(ma+mb)va = maua + mbub + mbCr(ua+ub)
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